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5w^2-17w+12=0
a = 5; b = -17; c = +12;
Δ = b2-4ac
Δ = -172-4·5·12
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-7}{2*5}=\frac{10}{10} =1 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+7}{2*5}=\frac{24}{10} =2+2/5 $
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